数字读取和输出
it1352
帮助5人
问题说明
好的，我遇到了一些麻烦，我可以让程序读取所有整数，但现在我很困惑如何让程序读取奇数或偶数，然后只添加奇数和偶数，给出总计两者
Ok I'm having a little trouble I can get the program to read all the integers but now I'm confused how to get the program to read that is odd or even then add only odd and only even, giving totals for both
def main():
myfile = open('numbers.txt','r')
for line in myfile:
print(line)
myfile.close()
myfile=open('numbers.txt','r')
num1=int(myfile.readline())
num2=int(myfile.readline())
num3=int(myfile.readline())
num4=int(myfile.readline())
num5=int(myfile.readline())
num6=int(myfile.readline())
num7=int(myfile.readline())
num8=int(myfile.readline())
num9=int(myfile.readline())
num10=int(myfile.readline())
num11=int(myfile.readline())
num12=int(myfile.readline())
myfile.close()
total=num1 num2 num3 num4 num5 num6 num7 num8 num9 num10 num11 num12
print('The numbers are:',num1,num2,num3,num4,num5,num6,num7,num8,num9,num10,num11,num12)
print('Their total is:',total)
main()
正确答案
#1
这里有一个解决方案，避免使用太多变量:
here is a solution, to avoid using too many variables:
def getOddEven(fileName):
odd = 0
even = 0
print ('The numbers are: ')
with open(fileName, 'r') as myfile:
for line in myfile:
print(line),
try:
number = int(line)
if (number%2 == 0):
even =number
else:
odd =number
except:
pass
return odd,even
def main():
odd, even = getOddEven('numbers.txt')
print('\nTheir total is:',odd even)
print('Total of odd numbers is: ', odd)
print('Total of even numbers is: ', even)
if __name__ == '__main__':
main()
这篇好文章是转载于：学新通技术网
