bash脚本 - 遍历查找的输出
it1352
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问题说明
我有，我需要遍历find命令的输出中的每行一个bash脚本，但现在看来，我遍历从find命令每个单词（分隔空间）。我的脚本看起来像这样至今：
I have a bash script in which I need to iterate over each line of the ouput of the find command, but it appears that I am iterating over each Word (space delimited) from the find command. My script looks like this so far:
folders=`find -maxdepth 1 -type d`
for $i in $folders
do
echo $i
done
我希望这给像输出：
I would expect this to give output like:
./dir1 and foo
./dir2 and bar
./dir3 and baz
但我insted的获得输出是这样的：
But I am insted getting output like this:
./dir1
and
foo
./dir2
and
bar
./dir3
and
baz
我在做什么错在这里？
What am I doing wrong here?
正确答案
#1
找到，你可以使用一个简单的模式遍历子目录：
Since you aren't using any of the more advanced features of find, you can use a simple pattern to iterate over the subdirectories:
for i in ./*/; do
echo "$i"
done
这篇好文章是转载于：学新通技术网
